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Total cards: 13•Content version: v4•Public deck•Updated: 8/1/2026

Card preview (13)

#1
Front (Question)

buffer solution

Back (Answer)

system that minimises pH changes when small amounts of an acid or a base are added

#2
Front (Question)

what are the 2 components in buffer solutions

Back (Answer)

• a weak acid - conjugate base

#3
Front (Question)

what do weak acids, HA remove?

Back (Answer)

added alkali

#4
Front (Question)

what do conjugate bases, A- remove?

Back (Answer)

added acid

#5
Front (Question)

what happens to the pH as the buffer works?

Back (Answer)

pH changes but only by a small amount

#6
Front (Question)

on addition of an acid, H+(aq)

Back (Answer)

• [H+(aq)] increases • H+(aq) ions react with the conjugate base, A-(aq) • equilibrium position shifts to the left, removing most of the H+(aq)

#7
Front (Question)

on addition of an alkali, OH-(aq)

Back (Answer)

• [OH-(aq)] increases • small concentration of H+(aq) ions react with OH-(aq) ions: H+(aq) + OH-(aq) → H₂O(l) • HA dissociate, shifting the equilibrium position to the right to restore most of H+(aq) ions

#8
Front (Question)

[H+(aq)] and [A-(aq)] for weak acids and buffers

Back (Answer)

for weak acids: [H+(aq)]= [A-(aq)] for buffers: [H+(aq)]≠ [A-(aq)]

#9
Front (Question)

calculate the pH when the buffer solution contains 0.100 moldm⁻³ CH₃COOH and 0.3 moldm⁻³ CH₃OONa. Ka (CH₃COOH)= 1.74X10⁻⁵ moldm⁻³

Back (Answer)

calculate [H+(aq)] from Ka, [HA(aq)], and [A-(aq)] [H+(aq)] = Ka X [CH₃COOH(aq)]/ [CH₃COO-(aq)] = 1.74X10⁻⁵ X0.1/0.3 = 5.80X10⁻⁶ moldm⁻³ find pH pH= -log[H+(aq)]=-log(5.80X10⁻⁶)= 5.24

#10
Front (Question)

what is the end point of a titration

Back (Answer)

• indicator contains equal concentrations of HA and A- - colour will be in between the 2 extreme colours

#11
Front (Question)

what is an indicator?

Back (Answer)

weak acid

#12
Front (Question)

what is the vertical section of a pH curve

Back (Answer)

pH increases on addition of a very small volume of base - acid and base concentration similar

#13
Front (Question)

equivalence point of the titration

Back (Answer)

volume of one solution that exactly reacts with the volume of the other solution