Back to marketplace

Chapter 7.8: Reduction of Alkynes

No description yet. This curated deck is ready for daily study.

Total cards: 8•Content version: v4•Public deck•Updated: 8/1/2026

Card preview (8)

#1
Front (Question)

What are the reagents of dissolving-metal reduction of an alkyne?

Back (Answer)

Na°/NH3

#2
Front (Question)

What is the purpose of a Lindlar catalyst?

Back (Answer)

 Stops a catalytic reduction after the addition of one mole of hydrogen

#3
Front (Question)

Describe the mechanism of hydroboration-protonolysis of an alkyne

Back (Answer)

o Internal alkynes react with borane to give a trialkenylborane o Treating a trialkenylborane with a carboxylic acid results in stereoselective replacement of boron by hydrogen: a cis-alkenyl group bonded to a boron is converted to a cis-alkene

#4
Front (Question)

Define Lindlar catalyst

Back (Answer)

finely powdered palladium metal deposited on solid calcium carbonate that has been specially modified with lead salts. Its particular use is as a catalyst for the reduction of an alkyne to a cis alkene

#5
Front (Question)

Describe the mechanism of catalytic reduction of an alkyne

Back (Answer)

o Treatment of an alkyne with H2 in the presence of a transition metal catalyst, most commonly palladium, platinum, or nickel, results in the addition of two moles of H2 to the alkyne and its conversion to an alkane

#6
Front (Question)

What is a finely powdered palladium metal deposited on solid calcium carbonate that has been specially modified with lead salts. Its particular use is as a catalyst for the reduction of an alkyne to a cis alkene?

Back (Answer)

Lindlar catalyst

#7
Front (Question)

What is the stereochemistry of dissolving-metal reduction of an alkyne

Back (Answer)

o Stereochemistry: anti  trans or E product

#8
Front (Question)

Describe the mechanism of dissolving-metal reduction of an alkyne

Back (Answer)

 Step 1: A one-electron reduction of the alkyne gives an alkenyl radical anion (an anion containing an unpaired electron on one carbon and a negative charge on an adjacent carbon)  Step 2: Add a proton  Step 3: A one-electron reduction of the alkenyl radical gives and alkenyl anion  Step 4: Add a proton