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p-block - periodicity + physical properties

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卡片总数: 24内容版本: v4公开卡包更新时间: 8/1/2026

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#1
正面 (问题)

p-block element definition

背面 (解答)

elements which have their valence electrons in p-orbitals

#2
正面 (问题)

what are the 3 types of element in the p-block?

背面 (解答)

non-metals, metalloids, metals

#3
正面 (问题)

how does atomic radii change across a period?

背面 (解答)

atomic radii tends to decrease across a period due to increasing effective nuclear force

#4
正面 (问题)

how does atomic radii change down a group?

背面 (解答)

atomic radii tends to increase down a group because of increasing principle QN meaning more shells, however increase down group is not linear, the change from row 2 to row 3 is significantly larger, this tells us row 2 elements are significantly smaller than row 3

#5
正面 (问题)

how are atomic radii values for p-block elements obtianed?

背面 (解答)

based on bonding atoms of that element, so elements that aren’t known to bond will not have these values

#6
正面 (问题)

electronegativity definition

背面 (解答)

the ability of an element to attract electrons in a chemical bond

#7
正面 (问题)

how does electronegativity change across a period?

背面 (解答)

electronegativity tends to increase across a period as effective nuclear charge increases and atomic radii decreases, leading to an increase in the attraction between nucleus and bonding electrons

#8
正面 (问题)

how does electronegativity change down a group?

背面 (解答)

electronegativity tends to decrease down a group as bonding electrons are further from the nucleus as atoms have more electron shells

#9
正面 (问题)

why do Ne/Ar not have known electronegativities?

背面 (解答)

they don’t form bonds

#10
正面 (问题)

how does electronegativity predict element type?

背面 (解答)

metals X <~2.00 metalloid X ~ 2.00 ~ 2.20 non metal X > ~ 2.20 - this is relatively accurate

#11
正面 (问题)

homonuclear single bond energy definition

背面 (解答)

the energy required to homolytically break a single bond between 2 atoms of the same element, represents bond strength - as homolytic fission this creates 2 radical species

#12
正面 (问题)

how does homonuclear single bond energy change across a period?

背面 (解答)

tends to increase across a period as electronegativity increases across a period, so elements attract bonding electrons more strongly so bonds get stronger - exceptionally group 14 –>15 sees a decrease in bond energy because group 15 elements still have lone pairs when saturated with bonds, which repel and weaken the bond

#13
正面 (问题)

how does homonuclear single bond energy change down a group?

背面 (解答)

tends to decrease down a group, except for between N->P, O->S, F->Cl this is because p-orbitals have n-2 radial nodes, so down a group radial nodes increases as principle QN n increases, reducing in-phase orbital overlap when bonds form, resulting in weaker bonds - exceptions is because lone pairs on N, O and F weakens their homonuclear single bonds, and as they also have very small atomic radii they have very short bond lengths so lone pair repulsion is greater, compared to row 3

#14
正面 (问题)

do p-block elements tend to form double bonds?

背面 (解答)

most p-block elements do not form double bonds

#15
正面 (问题)

do group 13 elements form double bonds + why?

背面 (解答)

group 13 elements have only 3 valence electrons, typically held in sp2 orbitals leaving an empty p-orbital which cannot form a π-bond as its empty

#16
正面 (问题)

do groups 17+18 form double bonds + why?

背面 (解答)

group 17+18 don’t need to form multiple bonds, due to the octet rule, both achieve an octet either naturally or after just one single bond

#17
正面 (问题)

are p-block elements more or less likely to form double bonds going down a group?

背面 (解答)

less likely as row 2 elements have very small atomic radii their single bonds are shorter, allowing atoms to be close enough to allow effective π-orbital overlap elements from row 3 down become much larger so π-orbital overlap is poorer - some row 3 elements can be forced to form double/triple bonds

#18
正面 (问题)

why can P + S form double bonds if row 3 elements?

背面 (解答)

P + S are the smallest row 3 elements able to form multiple bonds, groups 13 + 17 + 18 aren’t able to at all and the atomic radii of Si is too large so overlap is much poorer, although it ca sometimes be forced P + S aren’t yet that big and so have decent π-orbital overlap

#19
正面 (问题)

are double/triple bonds always stronger than single bonds?

背面 (解答)

yes

#20
正面 (问题)

why do some elements not naturally form multiple bonds if they are always stronger than single bonds?

背面 (解答)

this is based on the energy difference for forming a single bond vs multiple bonds - for N and O forming triple/doble bonds is favourable as their single bonds are much weaker due to lone pair repulsion, and they have good π-orbital overlap as they have short bond lengths, the energy cost of a double bond is < energy cost of 2 single bonds - same for triple - for P and S, π-orbital overlap isn’t as good and their single bonds are stronger, the energy cost of double bond > energy cost of 2 single bonds, so they prefer to form single bonds

#21
正面 (问题)

give the structures of the naturally occurring elements O, N, P, S

背面 (解答)

O=O N≡N P-P S-S (remember P and S don’t necessarily exist as diatomics)

#22
正面 (问题)

how does m.p/b.p change in p-block compounds?

背面 (解答)

in the absence of strong intermolecular interactions, m.p/b.p generally increases with Mr compounds with ionic/polymeric structures have high m.p/b.p that compounds with discrete molecular structures compounds that can hydrogen bond also have much higher m.p/b.p

#23
正面 (问题)

bronsted acid definition

背面 (解答)

proton donor

#24
正面 (问题)

bronsted base definition

背面 (解答)

proton acceptor