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The Formation of Halogenoalkanes

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Total cards: 24•Content version: v4•Public deck•Updated: 8/1/2026

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#1
Front (Question)

What is required for an alkane to react with a halogen?

Back (Answer)

Ultraviolet (UV) light is required to initiate the reaction

#2
Front (Question)

Why don’t alkanes react with halogens in the dark at room temperature?

Back (Answer)

There is not enough energy provided in the dark to break their strong C-C and C-H bonds

#3
Front (Question)

What type of reaction occurs between an alkane and a halogen under UV light?

Back (Answer)

Free radical substitution

#4
Front (Question)

Free radical substitution takes place in a chain reaction, what are the three stages involved?

Back (Answer)

1.Initiation 2.Propagation 3.Termination

#5
Front (Question)

What is the general overall equation for a free radical substitution reaction?

Back (Answer)

Alkane + Halogen → Halogenoalkane + Hydrogen halide

#6
Front (Question)

Write the balanced equation for the reaction of methane with chlorine?

Back (Answer)

CH4 + Cl2 ⇒ CH3Cl + HCl

#7
Front (Question)

What happens in the initiation step of free radical substitution?

Back (Answer)

The halogen bond (Cl-Cl) breaks to form two halogen radicals (Cl*)

#8
Front (Question)

Why is the UV light enough to cause the halogen bond (Cl-Cl) to break?

Back (Answer)

The energy fo one quantum of UV light is greater than the halogen bond energy

#9
Front (Question)

What type of bond fission occurs when the halogen bond (Cl-Cl) breaks?

Back (Answer)

Homolytic fission - one electron goes to each Cl atom

#10
Front (Question)

What is produced when the halogen bond (Cl-Cl) undergoes homolytic fission?

Back (Answer)

Two halogen (chlorine) free radicals (Cl*)

#11
Front (Question)

Why doesn’t the C-H bond in the alkane break during initiation?

Back (Answer)

It requires more energy than is provided by a quantum of UV light

#12
Front (Question)

What happens in the first propagation stage of free radical substitution Example methane reacting with chlorine

Back (Answer)

A halogen free radical (Cl) removes a hydrogen atom from the alkane (CH3), forming a hydrogen halide (HCl) and an alkyl radical (CH₃)

#13
Front (Question)

Write the equation for the first propagation step (methane and chlorine)

Back (Answer)

Cl* + CH₄ → HCl + *CH₃

#14
Front (Question)

What happens in the second propagation step? (methane and chlorine)

Back (Answer)

The alkyl radical (CH₃) reacts with another halogen molecule (Cl₂), forming a halogenoalkane (CH₃Cl) and a new halogen radical (Cl)

#15
Front (Question)

Write the equation for the second propagation step (methane and chlorine)

Back (Answer)

CH₃ + Cl₂ → CH₃Cl + Cl

#16
Front (Question)

What are the three overall products of the two propagation steps?

Back (Answer)

• A hydrogen halide (HCl) • A halogenoalkane (CH3Cl) • A side product depending on the radicals present (Cl*)

#17
Front (Question)

What happens during the termination step of free radical substitution? (methane and chlorine)

Back (Answer)

Free radicals (Cl* + CH3*)are removed by reacting together to form stable molecules

#18
Front (Question)

Write a termination reaction between two chlorine atoms

Back (Answer)

Cl* + Cl* → Cl₂

#19
Front (Question)

Write a termination reaction between two methyl radicals.

Back (Answer)

*CH₃ + *CH₃ → C₂H₆ (ethane)

#20
Front (Question)

Write a termination reaction between a chlorine radical and a methyl radical.

Back (Answer)

Cl* + *CH₃ → CH₃Cl

#21
Front (Question)

Why is termination less frequent than propagation?

Back (Answer)

Free radicals are low in concentration, despite being highly reactive, so mostly react with non - radical molecules instead

#22
Front (Question)

Can free radical substitution occur without UV light?

Back (Answer)

Yes, it can occur at high temperatures, even without light

#23
Front (Question)

What is a free radical? What is an electrophile?

Back (Answer)

An atom which has an unpaired electron An atom that is attracted to an electron rich region in another molecule

#24
Front (Question)

Why is the ozone layer important?

Back (Answer)

It protects the Earth from harmful exposure to, too many ultraviolet rays