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Topic 17.2 Carbonyl compounds

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Total cards: 24•Content version: v4•Public deck•Updated: 8/1/2026

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#1
Front (Question)

Carbonyl group

Back (Answer)

• A carbon atom joined by a double bond to an oxygen atom. • -C=O • Carbonyl compounds can be classed as either aldehydes or ketones.

#2
Front (Question)

Aldehydes

Back (Answer)

• A hydrogen atom is bonded to the carbonyl group. • General formula: RCHO • =O at the end of carbon chain • Aledehydes are oxidised further to produce carboxylic acids.

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#3
Front (Question)

Ketone

Back (Answer)

• There is only hydrocarbon groups joined to the carbonyl group. • Cannot be further oxidised as they do not have hydrogen atom attached to their carbonyl.

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#4
Front (Question)

Bonding in carbonyl compounds

Back (Answer)

• Contain -C=O group. • Polar bond. • Electron density is greater near the δ- O atom.

#5
Front (Question)

Physical properties in carbonyl compounds

Back (Answer)

• Distinctive smells. • Boiling temperature are between those of alkanes (low) and alcohol (high). • Boiling points increase with chain length. • No hydrogen bonding but permanent dipole dipole attraction.

#6
Front (Question)

Physical properties in ketones and aldehydes

Back (Answer)

• Smaller aldehydes and ketones are soluble in water - they can form hydrogen bonds with water. • Solubility decreases as chain length increases- hydrocarbon part of the molecules become more significant.

#7
Front (Question)

Primary alcohol

Back (Answer)

Oxidised: Primary alcohol —> aldehyde —> carboxylic acid

#8
Front (Question)

Secondary alcohol

Back (Answer)

Oxidised: Secondary alcohol —> ketone —> X

#9
Front (Question)

Tertiary alcohol

Back (Answer)

Tertiary alcohol —> X

#10
Front (Question)

Reagent observations: Felling’s reagent

Back (Answer)

Aldehyde: brick red, precipitate solid Ketone: stays blue, no visible change

#11
Front (Question)

Reagent observations: Tollen’s reagent

Back (Answer)

Aldehyde: silver mirror, black precipitate Ketone: stays colourless, no visible change

#12
Front (Question)

Reagent observations: sodium dichromate

Back (Answer)

Aldehydes: decolourises Ketones: stays purple, no visible change

#13
Front (Question)

Reagent observations: K2Cr2O7

Back (Answer)

Aldehyde: colour change, orange to green Ketone: stays orange, no visible change

#14
Front (Question)

Reaction with proponal/anone: Sodium dicromate

Back (Answer)

Propanal: green Propanone: orange (no change)

#15
Front (Question)

Reaction with proponal/anone: Felling’s solution

Back (Answer)

Propanal: light blue Propanone: dark blue

#16
Front (Question)

Reaction with proponal/anone: Tolling’s reagent

Back (Answer)

Propanal: white precipitate Propanone: colourless

#17
Front (Question)

Reduction reactions (eg. 2° alcohol –> 1° alcohol)

Back (Answer)

Aldehydes and ketones can be reduced to alcohols using lithium tetrahydridoaluminate (LiAlH4) dissolved in dry ether. -Reducing agent represented by [H]

#18
Front (Question)

Oxidation reactions

Back (Answer)

-Aldehydes can be oxidised to form carboxylic acids -Ketones are not easily oxidised (assume they aren’t) -Oxidising agents shown as [O]

#19
Front (Question)

Reactions with iodine

Back (Answer)

• Triidomethane reaction. • Carbonyl compound added to an alkaline solution of iodine. • Mixture warmed then cooled. • Yellow precipitate forms - this is a positive result. • Test for CH3CO group (found in ethanal and all methyl ketones).

#20
Front (Question)

Reaction with HCN

Back (Answer)

-Aldehydes and ketones react with HCN in an alkaline solution of KCN -These are addition reactions where a hydrogen atom joins to the oxygen in the carbonyl group and the cyanide group attaches to the carbon of the carbonyl group

#21
Front (Question)

Naming products

Back (Answer)

OH group- hydroxy CN group- nitrile The products are known as hydroxynitriles

#22
Front (Question)

Nucleophilic addition mechanism (Step 1)

Back (Answer)

Step 1: nucleophilic attack by a cyanide ion on the δ+ carbon atom of the carbonyl group.

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#23
Front (Question)

Nucleophilic addition mechanism (Step 2)

Back (Answer)

Step 2: the intermediate reacts with a hydrogen cyanide molecule.

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#24
Front (Question)

Optical activity

Back (Answer)

• As C=O is planar there is an equal chance of the CN- ion attacking from each side of the plane. • Even though the product contains a chiral centre, the product is not optically active as there are equal amounts of each enantiomer - a racemic mixture.