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ch 10

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卡片总数: 21内容版本: v4公开卡包更新时间: 8/1/2026

卡片预览 (21 张)

#1
正面 (问题)

phases of matter

背面 (解答)

solids, liquids and gases

#2
正面 (问题)

solids have

背面 (解答)

the strongest intermolecular forces and a fixed volume shape

#3
正面 (问题)

liquids have

背面 (解答)

a weaker intermolecular force and takes the shape of the container but not volume

#4
正面 (问题)

Gases

背面 (解答)

Fills the entire container (volume) takes the shape Intermolecular forces are very weak Lowest density of matter Particles do not interact much with each other

#5
正面 (问题)

Kinetic molecular theory

背面 (解答)

describes the behaviour of ideal gases

#6
正面 (问题)

T IS ALWAYS IN

背面 (解答)

K

#7
正面 (问题)

T (in K)=

背面 (解答)

T (in K)= T(in C + 273.15)

#8
正面 (问题)

Pressure formula

背面 (解答)

Pressure= Force/Area

#9
正面 (问题)

How do ideal gases behave?

背面 (解答)

1 ideal gases are in constant, random motion and move in straight lines 2 the volume of a volume gas is considered to be zero 3 They are elastic 4 There are no intermolecular forces (they dont attract or repel each other) 5 Temperature is directly proportional to the average kinetic energy of the gas particle

#10
正面 (问题)

Any gas behaves ideally in what conditions

背面 (解答)

Any gas behaves ideally in low pressures and high temperatures

#11
正面 (问题)

What would happen if gases had volume

背面 (解答)

They would be large and have more intermolecular forces to each other. They would react less with the walls and result in a decrease of pressure

#12
正面 (问题)

What would happen if collisions were not elastic?

背面 (解答)

Over time the particles would hit the walls with less force and there would be a decrease in pressure

#13
正面 (问题)

SI unit of pressure

背面 (解答)

1 Pa = 1N/m^2

#14
正面 (问题)

atmospheric pressure

背面 (解答)

1 atm=1bar

#15
正面 (问题)

avogradro says

背面 (解答)

more particles=larger volume volume in gas is directly proportional to the number of moles in the gas

#16
正面 (问题)

Avogadros law

背面 (解答)

Vn=k, where V is the volume of the gas, n is the number of moles of the gas, and k is a proportionality constant.

#17
正面 (问题)

Boyle says

背面 (解答)

higher pressure, smaller volume

#18
正面 (问题)

boyle law

背面 (解答)

P1V1=P2V2 where mols and temperature are constant

#19
正面 (问题)

Charles says

背面 (解答)

The higher the temperature the larger the volume

#20
正面 (问题)

Charles law

背面 (解答)

V₁ / T₁ = V₂ / T₂, where V₁ and T₁ are the initial volume and temperature, respectively. Similarly, V₂ and T₂ are the final values of these gas parameters. Where mols and pressure are constant

#21
正面 (问题)

All the laws combined gives

背面 (解答)

The ideal gas law PV=nRT P=atm V=L T=K