Amines
No description yet. This curated deck is ready for daily study.
Card preview (24)
nitrobenzene with H2/Pd or Fe/HCl or Sn/HCl gives
aniline ntribenezene gets reduced to aniline
why is the reaction of nitrobenzene to aniline preferred with Fe/HCl
because FeCl2 formed get hydrolyzed to release hydrochloric acid during the reaction thus only a small amount of hydrochloric acid is required to initiate the reaction
Nitrilesd gets reduced to _______by LiAlH4 and H2/Pd
primary amine
amides are reduced to ____ by LiAlH4
Primary amines
whats formed when ammonia is reacted with a alkyl halide and what is the end product after multiple such process and how to get amine from that and which type of amine is formed?
ammonia with alkyl Halide forms R-NH3X –> R-NH2 this keeps on going till R4NX amine can be obtained by treating R-NH3X with NaOH resulting in R-NH2 https://imgur.com/JeKATrN
Whats Gabriel Phtalimide synthesis
write the hoffmann bromamide degradation reaction
why are amines more soluble in alcohol ether and benzene
because they are more polar than amines and form stronger intermolecular hydrogen bonds than amines
boiling point comparision in primary,secondary and tertiary Amines
Primary>Secondary>Tertiary
aniline with K2Cr2O7 forms?
the intermoleceluar association in primary amines is less or more than the intermolecular association in secondary amines
less
R-CN with DIBAL-H forms?
R-CHO
phenyl cyanide with SnCl2+HCl forms?
wat a semicarbazone moleculue of acetone
why does aniline doesn’t gives friedal craft alkylation reaction?
because aniline does a acid-base reaction and forms a bond with AlCl3 which makes the benzene ring highly deactivated
amide with LiAlH4 forms!?
in the reaction of hypobromite with amide, the carbonyl carbon is lost as
CO3 ^2-
the product of 1 degree amine hinsberg test is soluble in what?
dil. NaOH
the purpose of NaOH in the ammonolysis reaction is to?
to remove the acidic impurities
diazonium ion with water forms
phenol
mst suitable reagent for converting nitrile to primary amine is
LiAlH4
chlorobenzene forms the maximum/minimum yield in friedal alkylation reaction
maximum