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8: Energetics I

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Total cards: 11•Content version: v4•Public deck•Updated: 8/1/2026

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#1
Front (Question)

What are standard conditions?

Back (Answer)

100 kPa 298 K

#2
Front (Question)

State what is meant by the enthalpy change?

Back (Answer)

The heat energy change measured at constant pressure

#3
Front (Question)

Define standard enthalpy change of reaction

Back (Answer)

The enthalpy change when - Substances react together - In the mole quantities given in the equation - Under standard conditions (100 kPa, 298 K)

#4
Front (Question)

Define standard enthalpy change of formation

Back (Answer)

The enthalpy change when - 1 mole of a substance is formed - from its elements in their standard states - Under standard conditions (100 kPa, 298 K)

#5
Front (Question)

Define standard enthalpy change of combustion

Back (Answer)

The enthalpy change when - 1 mole of a substance - is burnt completely in excess oxygen - Under standard conditions (100 kPa, 298 K)

#6
Front (Question)

Define standard enthalpy change of neutralisation

Back (Answer)

The enthalpy change when - 1 mole of water is formed - from the reaction between an acid and an alkali - Under standard conditions (100 kPa, 298 K)

#7
Front (Question)

When measuring standard enthalpy change of combustion, what reasons could cause a difference in the experimental value and the theoretical value?

Back (Answer)

Heat losses to the surroundings Incomplete combustion

#8
Front (Question)

What assumptions are made when measuring enthalpy change?

Back (Answer)

• No energy is lost to the surroundings • The density of a solution is 1.00 g cm^-3 • The SHC of a solution is 4.18

#9
Front (Question)

State Hess’s Law.

Back (Answer)

The enthalpy change for a reaction is independent of the route taken.

#10
Front (Question)

What is bond enthalpy?

Back (Answer)

The energy needed to break a bond (The same as the energy released when the bond is formed)

#11
Front (Question)

How do you calculate the enthalpy change of a reaction using the mean bond enthalpies?

Back (Answer)

Enthalpy change = bonds broken - bonds formed