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Chapter 13 - Soluability & Concentration

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卡片总数: 19内容版本: v4公开卡包更新时间: 8/1/2026

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#1
正面 (问题)

Solubility

背面 (解答)

The maximum amount of solute that can be dissolved in a certain volume of solvent at a given temperature, measured in g/100g.

#2
正面 (问题)

Saturated Solution

背面 (解答)

A solution that cannot dissolve anymore solute into it.

#3
正面 (问题)

Unsaturated Solution

背面 (解答)

A solution that can still dissolve solute into it.

#4
正面 (问题)

Supersaturated Solution

背面 (解答)

A solution that contains more solute that a saturated solution, making it unstable. Will readily form a precipitate.

#5
正面 (问题)

Solubility Curve

背面 (解答)

A graph showing the change in solubility as temperature changes.

#6
正面 (问题)

Solvent

背面 (解答)

The substance that the solute is dissolved into.

#7
正面 (问题)

Solute

背面 (解答)

The substance that dissolves in the solvent.

#8
正面 (问题)

Solution

背面 (解答)

A homogeneous (evenly distributed) mixture of two or more substances (a solute and solvent).

#9
正面 (问题)

Crystallisation

背面 (解答)

The process of creating solids (crystals) as a saturated solution cools or evaporates.

#10
正面 (问题)

Concentration

背面 (解答)

The amount of solute that is dissolved in a solution.

#11
正面 (问题)

Dilute

背面 (解答)

A solution that has low amounts of solute.

#12
正面 (问题)

Concentrated

背面 (解答)

A solution that has high amounts of solute.

#13
正面 (问题)

Concentration (grams/litre)

背面 (解答)

mass of solute (grams) / volume of solution (litres)

#14
正面 (问题)

Concentration (parts per million; ppm)

背面 (解答)

mass of solute (milligrams) / volume of solution (kg)

#15
正面 (问题)

Concentration (percentage by volume; v/v)

背面 (解答)

volume of solute / volume of solution x 100

#16
正面 (问题)

Concentration (mass by volume; m/v)

背面 (解答)

mass of solute (grams) / volume of solution (millilitres) x 100

#17
正面 (问题)

Concentration (moles/litre)

背面 (解答)

c = n / V (concentration in molar = amount of mol / volume in litres)

#18
正面 (问题)

Molarity

背面 (解答)

Concentration measured in the unit mol/L or molar (M).

#19
正面 (问题)

Dilution Formula

背面 (解答)

c1V1 = c2V2 (initial concentration x initial volume = final concentration x final volume).