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1 Moles 2

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卡片总数: 24内容版本: v4公开卡包更新时间: 8/1/2026

卡片预览 (24 张)

#1
正面 (问题)

A solution of HCl is 1 M What does the M stand for?

背面 (解答)

M stands for Molar M = mole / dm3

#2
正面 (问题)

Rearrange the concentration equation in terms of moles

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背面 (解答)

n = C V

#3
正面 (问题)

What volume does 0.5 moles of chlorine gas occupy?

背面 (解答)

12 dm3 V = n x molar volume = 0.5 mole x 24dm3/mol = 12dm3 1 mole of any gas occupies 24dm3

#4
正面 (问题)

50 cm3 of NaOH was added to the acid. What is this volume in dm3?

背面 (解答)

1000 cm3 = 1 dm3 50 cm3 / 1000 = 0.050 dm3

#5
正面 (问题)

Why must we use a burette when titrating?

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背面 (解答)

It allows us to measure any amount of acid/alkali with a small uncertainty. We can also add drop by drop near the end point (neutralisation point) This burette - if used properly - measures to +- 0.1 cm3

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#6
正面 (问题)

How many moles are there in 24 dm3 of carbon dioxide gas?

背面 (解答)

1 mole of carbon dioxide molecules 1 mole of any gas occupies 24dm3 at room temp

#7
正面 (问题)

During titration, why must we use a pipette to measure out the solution into the conical flask?

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背面 (解答)

Using a pipette decreases the uncertainty in our volume reading If this pipette is used properly it measures to +- 0.03 cm3 !!

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#8
正面 (问题)

What colour is methyl orange in acid and alkali?

背面 (解答)

red in acid yellow in alkali

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#9
正面 (问题)

What is the relationshipe between moles, mass and RFM

背面 (解答)

moles = mass/ RFM

#10
正面 (问题)

Define concentration

背面 (解答)

Concentration is moles per unit volume of a solution

#11
正面 (问题)

Why must you swirl your conical flask during titration?

背面 (解答)

To fully mix the acid and alkali - ensure that the reaction is complete.

#12
正面 (问题)

Does using a pipette and burette which both measure volume to a high resolution improve the accuracy or reliability of your results?

背面 (解答)

Using a pipette and burette and reading these at eye level and to the bottom of the meniscus improves the accuracy of your results.

#13
正面 (问题)

Read the burette below

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背面 (解答)

42.30 cm3 Do not forget to add the zero - you can tell if it is exactly on the 0.30 or if it is 0.35!!

#14
正面 (问题)

What do we call the process of filling a burette on the floor using a funnel?

背面 (解答)

This is called ‘charging’ the burette

#15
正面 (问题)

What colour is litmus in alkali?

背面 (解答)

blue

#16
正面 (问题)

2H2 + O2 ⇒ 2H2O What volume of oxygen is needed to fully react with 30 dm3 of hydrogen?

背面 (解答)

2H2 + 1O2 ⇒ 2H2O 15dm3 of oxygen 1 mole of any gas occupies the same volume- therefore use the short cut! Mole ratio of H2 : O2 is 2 : 1

#17
正面 (问题)

What are concordant results?

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背面 (解答)

Concordant results are when the volume of solution added are within 0.2 cm3 of each other. Any concordant results are then averaged.

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#18
正面 (问题)

What colour is litmus in acid?

背面 (解答)

red

#19
正面 (问题)

25.00 cm3 of sodium hydroxide was added to a conical flask. 10.0 cm3 of 2M hydrochloric acid was needed to neutralise the sodium hydroxide. Calculate the moles of HCl used.

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背面 (解答)

n = CV n = 2M x 0.010 dm3 =0.02 mol

#20
正面 (问题)

20.00 cm3 of sodium hydroxide was added to a conical flask. 10.0 cm3 of 2M hydrochloric acid was needed to neutralise the sodium hydroxide. n = CV n = 2M x 0.010 dm3 =0.02 mol of acid was used HCl : NaOH is a 1:1 mole ratio Therefore 0.02 mol of NaOH reacted Calculate the concentration of NaOH?

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背面 (解答)

C = n/V C = 0.02 / 0.020 = 1 mol/dm3 OR 1M

#21
正面 (问题)

Name the equipment below

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背面 (解答)

A- volumetric flask B- pipette C- burette

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#22
正面 (问题)

What steps do you follow when calculating the concentration of an acid needed to neutralise a known concentration of alkali?

背面 (解答)

• Use n = CV to find moles of alkali • Use mole ratio between acid and alkali from balanced equation • used C = n/V to find concentration of acid DO NOT FORGET - VOLUME MUST BE IN dm3

#23
正面 (问题)

What volume does 1 moles of ammonia gas occupy?

背面 (解答)

24 dm3 V = n x molar volume = 1 mol x 24dm3/mol= 24dm3 1 mole of any gas occupies 24dm3

#24
正面 (问题)

2H2 + O2 ⇒ 2H2O What volume of hydrogen is needed to fully react with 20 dm3 of oxygen?

背面 (解答)

2H2 + 1O2 ⇒ 2H2O <——— 40dm3 of hydrogen 1 mole of any gas occupies the same volume- therefore use the short cut! Mole ratio of O2 : H2 is 1 : 2