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2.1.3 amount of substance

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Total cards: 23•Content version: v4•Public deck•Updated: 8/1/2026

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#1
Front (Question)

Mole

Back (Answer)

Amount of substance in grams that has the same number of particles as there are atoms in 12 grams of carbon-12

#2
Front (Question)

Relative atomic mass

Back (Answer)

Average mass of one atom compared to 1/12th of the mass of one atom of carbon-12

#3
Front (Question)

Molar mass

Back (Answer)

Mass in grams of 1 mole of a substance g mol-1

#4
Front (Question)

Calculating molar mass

Back (Answer)

Adding up the mass numbers (from the periodic table) of each element in the compound

#5
Front (Question)

Molar gas volume

Back (Answer)

Volume of 1 mole of a gas at a given temperature and pressure. All gases have this same volume At room pressure (1atm) and room temperature (25C) the molar gas volume is 24dm3 mol-1

#6
Front (Question)

Avogadro’s constant

Back (Answer)

6.02x10^23 atoms in 12 grams of carbon-12

#7
Front (Question)

Amount in mol calculation

Back (Answer)

Moles = grams/ RAM

#8
Front (Question)

Empirical formulae

Back (Answer)

Simplest whole number ratio of atoms of each element in the compound

#9
Front (Question)

Empirical formulae method

Back (Answer)

• Divide each mass by the atomic mass of the element • Divide each number by the smallest one • Sometimes you may need to multiply to get whole numbers

#10
Front (Question)

Molecular formula

Back (Answer)

Actual number of atoms of each element in the compound

#11
Front (Question)

Hydrated salt

Back (Answer)

Contains water of crystallisation

#12
Front (Question)

Method for measuring mass loss / mass gain when reacting magnesium with oxygen

Back (Answer)

Heating in a crucible • Weigh an empty dry crucible and lid • Add 2g of hydrated CaSO4 to the crucible and weigh again • Heat strongly with a Bunsen for a couple of minutes • Allow to cool • Weigh crucible and contents again • Heat crucible again and reweigh until you reach a constant mass

#13
Front (Question)

Concentration calculation

Back (Answer)

Concentration = moles / volume dm3

#14
Front (Question)

mass concentration calculation

Back (Answer)

Mass concentration = mass / volume g dm3

#15
Front (Question)

Making a solution

Back (Answer)

Weigh sample bottle containing required mass of solid on 2dp balance Transfer to beaker and re weigh bottle Record difference in mass Add 100cm3 distilled water to beaker. Use glass rod to stir to help dissolve the solid Pour solution into 250cm3 graduated flask via a funnel Rinse beaker and funnel and add washings from beaker and glass rod to volumetric flask Make up to the mark with distilled water using a dropping pipette Invert flask several times to ensure uniform solution

#16
Front (Question)

Diluting a solution

Back (Answer)

Pipette 25cm3 of original solution into 250cm3 volumetric flask Make up to the mark with distilled water using a pipette for last few drops Invert flask several times to ensure uniform solution

#17
Front (Question)

Calculating dilutions

Back (Answer)

New diluted concentration = original concentration x (original volume / new diluted volume)

#18
Front (Question)

Safety and hazards

Back (Answer)

Irritant - dilute acid and alkalis- wear googles Corrosive- stronger acids and alkalis wear goggles Flammable – keep away from naked flames Toxic – wear gloves- avoid skin contact- wash hands after use Oxidising- Keep away from flammable / easily oxidised materials

#19
Front (Question)

Gas volume calculation

Back (Answer)

Gas volume dm3 = amount x 24

#20
Front (Question)

No particles calculation

Back (Answer)

Amount of substance (in mol) x avogadros constant

#21
Front (Question)

Density calculation

Back (Answer)

Density = mass / volume G cm-3

#22
Front (Question)

Percentage yield calculation

Back (Answer)

Percentage yield = (actual yield/theoretical yield) x 100 • Work out moles of reactant • Use balanced equation to give moles of product • Work out mass of product • Use equation

#23
Front (Question)

Percentage atom economy calculation

Back (Answer)

Atom economy = (mass of useful products/ mass of all reactants) x 100 So, (moles x Mr of product) / (moles x mr of reactant (do all)) x100