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Thermodynamics (P1+P3)

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Total cards: 24•Content version: v4•Public deck•Updated: 8/1/2026

Card preview (24)

#1
Front (Question)

Define standard enthalpy of formation

Back (Answer)

Enthalpy change when 1 mole of a compound is formed from its elements under standard conditions, all reactants and products in their standard states. Na(s) + 1/2Cl2(g) –> NaCl(s)

#2
Front (Question)

Define 1st ionisation enthalpy

Back (Answer)

Standard enthalpy change when 1 mole of electrons is removed from 1 mole of atoms to give 1 mole of gaseous ions with a single positive charge. Ca(g) –> Ca+(g) + e-

#3
Front (Question)

Define standard enthalpy of atomisation

Back (Answer)

Enthalpy change when 1 mole of gaseous atoms are formed from an element in its standard state. 1/2Br2(l) –> Br(g)

#4
Front (Question)

Define mean bond enthalpy

Back (Answer)

Enthalpy change when 1 mole of gaseous molecules each break a covalent bond to form 2 free radicals over a range of compounds. Br2(l) –> 2Br(g)

#5
Front (Question)

Define 1st electron affinity

Back (Answer)

Standard enthalpy change when 1 mole of gaseous atoms is converted into 1 mole of gaseous ions each with a single negative charge under standard conditions. O(g) + e- –> O-(g)

#6
Front (Question)

Define lattice formation enthalpy

Back (Answer)

Standard enthalpy change when 1 mole of a solid ionic compound is formed from its gaseous ions. Mg2+(g) + 2Br(g) –> MgBr2(s)

#7
Front (Question)

Define lattice dissociation enthalpy

Back (Answer)

Enthalpy change when 1 mole of solid ionic compound dissociates into its gaseous ions. MgBr2(s) –> Mg2+(g) +2Br-(g)

#8
Front (Question)

Define standard enthalpy of hydration

Back (Answer)

Standard enthalpy change when 1 mole of gaseous ions in converted into 1 mole of aqueous ions. Cl-(g) + aq –> Cl-(aq)

#9
Front (Question)

Define standard enthalpy of solution

Back (Answer)

Standard enthalpy change when 1 mole of a solute dissolves to form its aqueous ions. NaCl(s) + aq –> Na+(aq) + Cl-(aq)

#10
Front (Question)

How does charge and ionic radius determine how exothermic a lattice will be?

Back (Answer)

The bigger the charge and the smaller the ion, the greater the charge density.

#11
Front (Question)

The more negative the lattice formation means…

Back (Answer)

More stronger ionic bonds

#12
Front (Question)

How to determine if a compound will have covalent character

Back (Answer)

• A positive ion which is small and highly charged. • A negative ion which is large and negatively charged.

#13
Front (Question)

The perfect ionic (theoretical) model suggests that…

Back (Answer)

Ions have point charges and are perfectly ionic.

#14
Front (Question)

The born haber cycle (experimental) suggests that…

Back (Answer)

Ions are polarisable and have SOME covalent character.

#15
Front (Question)

If an ionic compound has NO covalent character…

Back (Answer)

∆HLf value for perfect ionic model and experimental model would be very similar

#16
Front (Question)

If an ionic compound HAS covalent character…

Back (Answer)

∆HLf value calculated by the perfect ionic model should be less exothermic than the ∆HLf calculated by the experimental born haber cycle

#17
Front (Question)

Define entropy

Back (Answer)

A measure of disorder in a system.

#18
Front (Question)

What happens to the entropy from a solid to a liquid to a gas?

Back (Answer)

Increases

#19
Front (Question)

What happens to the entropy from a gas to a liquid to a solid?

Back (Answer)

Decreases

#20
Front (Question)

What happens to the entropy from a small number of moles to a large number of moles?

Back (Answer)

Increases

#21
Front (Question)

What happens to the entropy from a large number of moles to a small number of moles?

Back (Answer)

Decreases

#22
Front (Question)

Equation for entropy (∆S)

Back (Answer)

Products - Reactants

#23
Front (Question)

Equation for Gibbs free energy (∆G)

Back (Answer)

∆G = ∆H - T∆S ∆H = enthalpy change Kj mol-1 T = temp in K ∆S = entropy change KjK-1mol-1 key point = divide ∆S by 1000

#24
Front (Question)

Equation to calculate the temperature at which the reaction becomes feasible?

Back (Answer)

T = ∆H / ∆S