返回卡包市场

5. Chemical Calculations HODDER

暂无描述。系统推荐的高质量记忆内容,适合每天坚持背诵学习。

卡片总数: 20内容版本: v4公开卡包更新时间: 8/1/2026

卡片预览 (20 张)

#1
正面 (问题)

Define a Mole.

背面 (解答)

The SI unit for amount of substance. It contains the same number of particles as there are atoms in 12g of Carbon-12.

#2
正面 (问题)

What is the Avogadro Constant?

背面 (解答)

The number of particles in one mole: 6.02 × 10²³.

#3
正面 (问题)

What is Molar Mass?

背面 (解答)

The mass of one mole of a substance in grams (numerically equal to the Mr or Ar).

#4
正面 (问题)

What is the Molar Gas Volume at RTP?

背面 (解答)

24 dm³ (or 24,000 cm³).

#5
正面 (问题)

State Avogadro’s Law.

背面 (解答)

At the same temperature and pressure, equal volumes of gases contain the same number of particles.

#6
正面 (问题)

Equation: Calculate Moles from Mass.

背面 (解答)

Moles = Mass / Mr

#7
正面 (问题)

Equation: Calculate Mass from Moles.

背面 (解答)

Mass = Moles × Mr

#8
正面 (问题)

Equation: Calculate Moles of Gas (at RTP).

背面 (解答)

Moles = Volume (in dm³) / 24

#9
正面 (问题)

How do you convert cm³ to dm³?

背面 (解答)

Divide by 1000.

#10
正面 (问题)

What is Percentage Purity?

背面 (解答)

(Mass of pure substance / Total mass of impure sample) × 100.

#11
正面 (问题)

What is Percentage Composition?

背面 (解答)

(Total Ar of element / Mr of compound) × 100.

#12
正面 (问题)

What is the Limiting Reactant?

背面 (解答)

The reactant that is completely used up in a reaction. It determines the amount of product made.

#13
正面 (问题)

What is the Reactant in Excess?

背面 (解答)

The reactant that is left over after the reaction stops.

#14
正面 (问题)

Steps to calculate Empirical Formula?

背面 (解答)

• Mass (or %) ÷ Ar (find moles). 2. Divide all moles by the smallest number (find ratio). 3. Round to nearest whole number.

#15
正面 (问题)

Difference between Empirical and Molecular Formula?

背面 (解答)

Empirical is the simplest ratio. Molecular is the actual number of atoms in the molecule.

#16
正面 (问题)

Calculate the mass of 0.5 moles of Water (H₂O).

背面 (解答)

Mr of H₂O = 18. Mass = 0.5 × 18 = 9g.

#17
正面 (问题)

How many atoms are in 1 mole of Oxygen gas (O₂)?

背面 (解答)

1.204 × 10²⁴ atoms. (1 mole of molecules = 6.02×10²³, multiply by 2 because O₂ is diatomic).

#18
正面 (问题)

You calculate moles using V/24. The volume is 480 cm³. Is the answer 20 moles?

背面 (解答)

NO. You must convert to dm³ first. 480/1000 = 0.48 dm³. Moles = 0.48/24 = 0.02 mol.

#19
正面 (问题)

Reaction: Mg + 2HCl -> MgCl₂ + H₂. If you have 1 mole of Mg and 1 mole of HCl, which is limiting?

背面 (解答)

HCl is limiting. The ratio is 1:2. You need 2 moles of HCl for every 1 mole of Mg, but you only have 1.

#20
正面 (问题)

You have a concentration of 36.5 g/dm³ of HCl. What is this in mol/dm³? (Mr of HCl = 36.5).

背面 (解答)

1.0 mol/dm³. (Mass Conc / Mr = 36.5 / 36.5 = 1).