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Periodicity

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Total cards: 17•Content version: v4•Public deck•Updated: 8/1/2026

Card preview (17)

#1
Front (Question)

Define first ionisation energy

Back (Answer)

The energy required to remove 1 mole of electrons from 1 mole of gaseous atoms of an element to form 1 mole of gaseous 1+ ions

#2
Front (Question)

How can you identify when a shell has been removed from a successive ionisation energy graph?

Back (Answer)

A large jump in the ionisation energy value

#3
Front (Question)

What is meant by sheilding?

Back (Answer)

The effect of the inner electrons shielding the outer electrons from the effect of the charge on the nucleus

#4
Front (Question)

What is meant by nuclear charge?

Back (Answer)

The positive charge on the nucleus

#5
Front (Question)

Describe the trend in atomic radius across period 3.

Back (Answer)

Atomic radius decreases across period 3. The increased number of protons create more positive charge attraction for the electrons in the same shell. Shielding also stays the same.

#6
Front (Question)

What is the shape of the general trend graph for first ionisation energies across any period?

Back (Answer)

A straight line originating at the origin

#7
Front (Question)

What is the trend in ionisation energy across period 3?

Back (Answer)

First ionisation energy increases across period 3 as the atomic radius decreases, but electrostatic attraction increases

#8
Front (Question)

Describe the actual trend in first ionisation energy across period 3

Back (Answer)

• Increases slightly from sodium to magnesium • Drops slightly from magnesium to aluminium • Increases significantly between aluminium and sillicon • Increases slightly between sillicon and phosphorus • Decreases between phosphorus and sulphur • Increases until the end of the period

#9
Front (Question)

Explain why aluminium has a lower first ionisation energy than magnesium.

Back (Answer)

• Aluminium has 1 electron in a higher subshell • This electron is removed more easily as it is further away from the nucleus • Therefore first ionisation energy is lower

#10
Front (Question)

What is the general trend in shielding, nuclear charge and atomic radius down a group?

Back (Answer)

All 3 increase

#11
Front (Question)

Why does nuclear attraction decrease down a group?

Back (Answer)

• Shielding and nuclear charge both increase, cancelling each other out

#12
Front (Question)

Explain the trend in first ionisation energy down a group.

Back (Answer)

The outer electrons are found in shells further away from the nucleus and are more shielded, so the attraction between the nucleus and those electrons decreases.

#13
Front (Question)

Why does melting point increase from Na - Al in period 3? (Metallic bonding)

Back (Answer)

• The charge on the metal ions increases from +1 to +3 • The number of delocalised electrons increases so the strength of the metallic bond increases • More energy is needed to break stronge metallic bonds so the melting point increases

#14
Front (Question)

Why does Si have a much higher melting point than all other period 3 elements? (Giant covelant)

Back (Answer)

• Si has a similar structure to the carbon atoms in diamond • Each Si atom is bonded to 4 other atoms • The covelant bonds are incredibly strong so a high amount of energy is needed to break them

#15
Front (Question)

Why do elements P - Ar in period 3 have a low melting point? (Simple covelant)

Back (Answer)

• When the 4 elements melt or boil, the weak London forces break. • Little energy is needed to overcome the forces so the melting point is low

#16
Front (Question)

What order does the melting points of period 3 simple covelang elements decrease in and why?

Back (Answer)

• S > P > Cl > Ar • There is more surface contact between sulphur molecules (S8) than phospurus molecules (P4) leading to stronger London forces and a higher melting point

#17
Front (Question)

Why is there a drop in first ionisation energy between phosphorus and sulphur?

Back (Answer)

• Sulphur has 4 electrons in the 3p subshell, so the orbital has 1 set of doubled up electrons. • When the 2nd electron is introduced to the now full orbital, there is a slight repulsion between both electrons, which makes the second easier to remove.